Beeler, M., Gosper, R.W., and Schroeppel, R. *HAKMEM*. MIT AI
Memo 239, Feb. 29, 1972.
Retyped and converted to *html* ('Web browser format) by
Henry Baker,
April, 1995.
## POLYOMINOS, ETC.

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### ITEM 108:

See the PROPOSED COMPUTER
PROGRAMS section for counts of polyominos of orders < 19.
### ITEM 109 (Schroeppel):

Tessellating the plane with polyominos:
Through all hexominos, the plane can be tessellated with each piece (without
even flipping any over). All but the four heptominos below can tessellate the
plane, again without being flipped over. Thus, flipping does not buy you
anything through order 7. (There are 108 heptominos).

`H H HHH H H
HHHHH H H HHHH HHHH
HH H H
H H
`

### ITEM 110 (Schroeppel):

PROBLEM: What rectangles are coverable by various polyominos? For example,
XX can cover rectangles which are 3N x M,
X except if N = 1, then M must be even.
YYYY can be shown by coloring to cover only rectangles
having at least one side divisible by four.

### ITEM 111 (Schroeppel):

PROBLEM: Find a necessary and sufficient condition for an arbitrary shape in
the plane to be domino coverable.
### ITEM 112 (Beeler):

"Iamonds" are made of equilateral triangles, like diamonds.
"(Poly-)ominos" are made of squares, like dominos.

"Hexafrobs" are made of hexagons.

"Soma-like" pieces are made of cubes.

See also "Polyiamonds", Math. Games, *Sci. Am.,* December 1964.
Left and right 3-dimensional forms are counted as distinct.

`ORDER IAMONDS OMINOS HEXA'S SOMA-LIKE
1 1 1 1 1
2 1 1 1 1
3 1 2 3 2
4 3 5 7 8
5 4 12 22 29
6 12 35
7 24
8 66
9 160
10 448
`

Polyominos of order 1, 2 and 3 cannot form a rectangle. Orders 4 and
6 can be shown to form no rectangles by a checkerboard coloring.
Order 5 has several boards and its solutions are documented
(*Communications of the ACM,* October 1965):
BOARD DISTINCT SOLUTIONS
3 X 20 2
4 X 15 368
5 X 12 1010
6 X 10 2339 (verified)
two 5 x 6 -- 2
8 x 8 with 2 x 2 hole in center -- 65

CONJECTURE (Schroeppel): If the ominos of a given order form rectangles of
different shapes, the rectangle which is more nearly square will have more
solutions.
Order-4 hexafrob boards and solution counts:

- side 7 triangle -- no solutions
- parallelogram, base 7, side 4 -- 9 distinct solutions, e.g.,
A A A A B C C
D E B B C F C
D E E B F G G
D D E F F G G

Order-6 iamond boards and solution counts (see
illustration):
- side 9 triangle with inverted side 3 triangle in center removed -- no
solutions
- trapezoid, side 6, bases 3 and 3+6 -- no solutions
- two triangles of side 6 -- no solutions
- trapezoid, side 4, bases 7 and 7+4 -- 76 distinct solutions
- parallelogram, base 6, side 6 -- 156 distinct solutions
- parallelogram, base 4, side 9 -- 37 distinct solutions
- parallelogram, base 3, side 12 --- no solutions
- triangle of side 9 with triangles of side 1, 2 and 2 removed from its corners
(a commercial puzzle) -- 5885 distinct solutions

With Soma-like pieces, orders 1, 2 and 3 do not have interesting boxes. Order
4 has 1390 distinct solutions for a 2 x 4 x 4 box. 1124 of these have the
four-in-a-row on an edge; the remaining 266 have that piece internal. 320
solutions are due to variations of ten distinct solutions decomposable into two
2 x 2 x 4 boxes. A soma-like 2 x 4 x 4 solution:
AAAA BBHH
BCCC BHHC
DDDE FGGE
FDGE FFGE

The commercial *Soma* has 240 distinct solutions; the booklet
which comes with it say this was found years ago on a 7094. Verified
by both Beeler and Clements.
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